Integrand size = 22, antiderivative size = 557 \[ \int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx=\frac {2^{-2-p} 3^{-p} e^{-\frac {6 a}{b}} \Gamma \left (1+p,-\frac {6 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^6 e^6}-\frac {3\ 5^{-p} d e^{-\frac {5 a}{b}} \Gamma \left (1+p,-\frac {5 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{2 c^5 e^6}+\frac {15\ 2^{-2 (1+p)} d^2 e^{-\frac {4 a}{b}} \Gamma \left (1+p,-\frac {4 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^4 e^6}-\frac {5\ 3^{-p} d^3 e^{-\frac {3 a}{b}} \Gamma \left (1+p,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^3 e^6}+\frac {15\ 2^{-2-p} d^4 e^{-\frac {2 a}{b}} \Gamma \left (1+p,-\frac {2 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^2 e^6}-\frac {3 d^5 e^{-\frac {a}{b}} \Gamma \left (1+p,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{2 c e^6} \]
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Time = 0.58 (sec) , antiderivative size = 557, normalized size of antiderivative = 1.00, number of steps used = 21, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {2504, 2448, 2436, 2336, 2212, 2437, 2346} \[ \int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx=\frac {2^{-p-2} 3^{-p} e^{-\frac {6 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {6 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^6 e^6}-\frac {3 d 5^{-p} e^{-\frac {5 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {5 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{2 c^5 e^6}+\frac {15 d^2 2^{-2 (p+1)} e^{-\frac {4 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {4 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^4 e^6}-\frac {5 d^3 3^{-p} e^{-\frac {3 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^3 e^6}+\frac {15 d^4 2^{-p-2} e^{-\frac {2 a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {2 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right )}{c^2 e^6}-\frac {3 d^5 e^{-\frac {a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )}{2 c e^6} \]
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Rule 2212
Rule 2336
Rule 2346
Rule 2436
Rule 2437
Rule 2448
Rule 2504
Rubi steps \begin{align*} \text {integral}& = \frac {3}{2} \text {Subst}\left (\int x^5 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right ) \\ & = \frac {3}{2} \text {Subst}\left (\int \left (-\frac {d^5 (a+b \log (c (d+e x)))^p}{e^5}+\frac {5 d^4 (d+e x) (a+b \log (c (d+e x)))^p}{e^5}-\frac {10 d^3 (d+e x)^2 (a+b \log (c (d+e x)))^p}{e^5}+\frac {10 d^2 (d+e x)^3 (a+b \log (c (d+e x)))^p}{e^5}-\frac {5 d (d+e x)^4 (a+b \log (c (d+e x)))^p}{e^5}+\frac {(d+e x)^5 (a+b \log (c (d+e x)))^p}{e^5}\right ) \, dx,x,x^{2/3}\right ) \\ & = \frac {3 \text {Subst}\left (\int (d+e x)^5 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{2 e^5}-\frac {(15 d) \text {Subst}\left (\int (d+e x)^4 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{2 e^5}+\frac {\left (15 d^2\right ) \text {Subst}\left (\int (d+e x)^3 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{e^5}-\frac {\left (15 d^3\right ) \text {Subst}\left (\int (d+e x)^2 (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{e^5}+\frac {\left (15 d^4\right ) \text {Subst}\left (\int (d+e x) (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{2 e^5}-\frac {\left (3 d^5\right ) \text {Subst}\left (\int (a+b \log (c (d+e x)))^p \, dx,x,x^{2/3}\right )}{2 e^5} \\ & = \frac {3 \text {Subst}\left (\int x^5 (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{2 e^6}-\frac {(15 d) \text {Subst}\left (\int x^4 (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{2 e^6}+\frac {\left (15 d^2\right ) \text {Subst}\left (\int x^3 (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{e^6}-\frac {\left (15 d^3\right ) \text {Subst}\left (\int x^2 (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{e^6}+\frac {\left (15 d^4\right ) \text {Subst}\left (\int x (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{2 e^6}-\frac {\left (3 d^5\right ) \text {Subst}\left (\int (a+b \log (c x))^p \, dx,x,d+e x^{2/3}\right )}{2 e^6} \\ & = \frac {3 \text {Subst}\left (\int e^{6 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{2 c^6 e^6}-\frac {(15 d) \text {Subst}\left (\int e^{5 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{2 c^5 e^6}+\frac {\left (15 d^2\right ) \text {Subst}\left (\int e^{4 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{c^4 e^6}-\frac {\left (15 d^3\right ) \text {Subst}\left (\int e^{3 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{c^3 e^6}+\frac {\left (15 d^4\right ) \text {Subst}\left (\int e^{2 x} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{2 c^2 e^6}-\frac {\left (3 d^5\right ) \text {Subst}\left (\int e^x (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )\right )\right )}{2 c e^6} \\ & = \frac {2^{-2-p} 3^{-p} e^{-\frac {6 a}{b}} \Gamma \left (1+p,-\frac {6 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^6 e^6}-\frac {3\ 5^{-p} d e^{-\frac {5 a}{b}} \Gamma \left (1+p,-\frac {5 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{2 c^5 e^6}+\frac {15\ 4^{-1-p} d^2 e^{-\frac {4 a}{b}} \Gamma \left (1+p,-\frac {4 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^4 e^6}-\frac {5\ 3^{-p} d^3 e^{-\frac {3 a}{b}} \Gamma \left (1+p,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^3 e^6}+\frac {15\ 2^{-2-p} d^4 e^{-\frac {2 a}{b}} \Gamma \left (1+p,-\frac {2 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{c^2 e^6}-\frac {3 d^5 e^{-\frac {a}{b}} \Gamma \left (1+p,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )\right )}{b}\right )^{-p}}{2 c e^6} \\ \end{align*}
\[ \int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx=\int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx \]
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\[\int x^{3} {\left (a +b \ln \left (c \left (d +e \,x^{\frac {2}{3}}\right )\right )\right )}^{p}d x\]
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\[ \int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx=\int { {\left (b \log \left ({\left (e x^{\frac {2}{3}} + d\right )} c\right ) + a\right )}^{p} x^{3} \,d x } \]
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Timed out. \[ \int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx=\text {Timed out} \]
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\[ \int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx=\int { {\left (b \log \left ({\left (e x^{\frac {2}{3}} + d\right )} c\right ) + a\right )}^{p} x^{3} \,d x } \]
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\[ \int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx=\int { {\left (b \log \left ({\left (e x^{\frac {2}{3}} + d\right )} c\right ) + a\right )}^{p} x^{3} \,d x } \]
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Timed out. \[ \int x^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )\right )\right )^p \, dx=\int x^3\,{\left (a+b\,\ln \left (c\,\left (d+e\,x^{2/3}\right )\right )\right )}^p \,d x \]
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